x^2+103x+603=0

Solution for x^2+103x+603=0 equation:

x^2+103x+603=0

a = 1; b = 103; c = +603;
Δ = b2-4ac
Δ = 1032-4·1·603
Δ = 8197
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(103)-\sqrt{8197}}{2*1}=\frac{-103-\sqrt{8197}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(103)+\sqrt{8197}}{2*1}=\frac{-103+\sqrt{8197}}{2}
$